Timeline for Are the groups $C( \mathbb{R} ; U(n) )$ isomorphic?
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 18, 2013 at 21:24 | vote | accept | Ollie | ||
| Apr 18, 2013 at 21:24 | answer | added | Ollie | timeline score: 2 | |
| Apr 18, 2013 at 7:20 | answer | added | Makoto Yamashita | timeline score: 6 | |
| Apr 16, 2013 at 18:52 | comment | added | Alain Valette | I think that the $C(X,U(n))$'s can be distinguished by observing that the minimal degree of a unitary irreducible representation of $C(X,U(n))$, not of degree 1, must be $n$. | |
| Apr 16, 2013 at 18:39 | comment | added | Ollie | You're right - I was thinking too algebraically and had completely missed that! Thanks | |
| Apr 16, 2013 at 18:28 | history | edited | Ollie | CC BY-SA 3.0 |
edited title
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| Apr 16, 2013 at 18:24 | comment | added | Will Sawin | Per Qiaochu's comment, aren't these obviously homomotopic to $U(n)$? | |
| Apr 16, 2013 at 18:15 | comment | added | Ollie | Yes, it denotes the unitary group, I've changed it now. | |
| Apr 16, 2013 at 18:10 | history | edited | Ollie | CC BY-SA 3.0 |
deleted 38 characters in body
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| Apr 16, 2013 at 17:53 | comment | added | Todd Trimble | Is $\mathcal{U}(n)$ supposed to be the unitary group? (If so, I thought just plain $U(n)$ was much more standard notation.) | |
| Apr 16, 2013 at 17:45 | comment | added | Qiaochu Yuan | I would guess that it's easier to prove that they aren't homotopy-equivalent. | |
| Apr 16, 2013 at 16:37 | history | asked | Ollie | CC BY-SA 3.0 |