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Apr 18, 2013 at 8:28 vote accept eb80
Apr 18, 2013 at 8:28 vote accept eb80
Apr 18, 2013 at 8:28
Apr 16, 2013 at 22:09 answer added George Lowther timeline score: 3
Apr 16, 2013 at 21:10 answer added Bazin timeline score: 2
Apr 16, 2013 at 21:03 answer added Liviu Nicolaescu timeline score: 2
Apr 16, 2013 at 16:35 comment added D. Kelleher This isn't really a satisfying answer, so i've made it a comment, but the Laplacian is an elliptic operator, so if $\Delta f\in C^\infty$ then so is $f$, at least for square integrable $f$.
Apr 16, 2013 at 15:51 history asked eb80 CC BY-SA 3.0