Timeline for Are virtual cubulated groups cubulated?
Current License: CC BY-SA 3.0
14 events
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| May 7, 2013 at 14:24 | history | edited | Lee Mosher |
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| Apr 20, 2013 at 12:09 | vote | accept | Dieter | ||
| Apr 19, 2013 at 13:08 | answer | added | HJRW | timeline score: 9 | |
| Apr 17, 2013 at 22:02 | answer | added | Ian Agol | timeline score: 4 | |
| Apr 17, 2013 at 11:00 | comment | added | HJRW | Dieter: I will when I have time. | |
| Apr 17, 2013 at 7:26 | comment | added | Dieter | HW: why not post the hyperbolic case as an answer? | |
| Apr 16, 2013 at 17:46 | comment | added | Misha | HW: I think, you are right about the hyperbolic case, it simply a corollary of Sageev's theorem. In the general case, I think, affine Coxeter group $\tilde{A}_2$ should give a counter-example. | |
| Apr 16, 2013 at 12:57 | history | edited | Dieter | CC BY-SA 3.0 |
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| Apr 16, 2013 at 12:56 | comment | added | HJRW | Specifically, I think you can deduce the word-hyperbolic case from Sageev's theorem (see, for instance, Theorem 7.1 of arXiv:1209.1074v2). | |
| Apr 16, 2013 at 12:48 | history | edited | Dieter | CC BY-SA 3.0 |
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| Apr 16, 2013 at 12:36 | history | edited | Max Horn |
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| Apr 16, 2013 at 12:29 | comment | added | HJRW | You probably already know that one gets an induced action of $G$ on the direct product of $|G:N|$ copies of the cube complex. The difficulty is to find a convex subcomplex on which $G$ acts cocompactly. In general, of course, this doesn't exist (consider, for instance, $2\mathbb{Z}\subseteq\mathbb{Z}$. Probably it's OK when $G$ is word-hyperbolic. | |
| Apr 16, 2013 at 11:50 | history | edited | Dieter | CC BY-SA 3.0 |
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| Apr 16, 2013 at 11:44 | history | asked | Dieter | CC BY-SA 3.0 |