Timeline for Constructing a stack (gerbe) from a connected groupoid
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Apr 16, 2013 at 17:24 | comment | added | Mikhail Borovoi | @DavidRoberts: Thank you for your detailed answer. This is exactly the kind of answer that I wanted to get! | |
| Apr 16, 2013 at 4:43 | history | edited | David Roberts♦ | CC BY-SA 3.0 |
edited body
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| Apr 15, 2013 at 22:51 | comment | added | David Roberts♦ | Whoops, you're right. And isomorphisms are bijections in this case. | |
| Apr 15, 2013 at 13:48 | vote | accept | Mikhail Borovoi | ||
| Apr 15, 2013 at 11:49 | comment | added | Mikhail Borovoi | Probably when you write "such that $\pi(a(p,f))=\pi(a)$", you mean $\pi(a(p,f))=\pi(p)$. When you write "in addition, we demand that the map $\dots$ is an isomorphism", you mean a bijection. Is this correct? | |
| Apr 15, 2013 at 10:50 | history | edited | David Roberts♦ | CC BY-SA 3.0 |
deleted 79 characters in body
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| Apr 15, 2013 at 10:45 | comment | added | David Roberts♦ | Yes, it's a typo. I'm going to improve the post.. | |
| Apr 15, 2013 at 10:31 | comment | added | Mikhail Borovoi | I do not understand the line: "isomorphic to $T\times_X S$ for some map $T\to X$". What is the map $S\to X$ in the fibered product? Is it a typo? | |
| Apr 15, 2013 at 7:00 | history | answered | David Roberts♦ | CC BY-SA 3.0 |