Timeline for wreath product and matrix presentation
Current License: CC BY-SA 3.0
15 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 15, 2013 at 13:08 | comment | added | j.p. | @Geoff: Yes, $r-1$ not $r$. | |
| Apr 14, 2013 at 6:31 | vote | accept | user27932 | ||
| Apr 13, 2013 at 15:57 | comment | added | Geoff Robinson | @jp: But I think you mean a Sylow $2$-subgroup of ${\rm GL}(2^{r-1},q)$) when $q \equiv 3$ (mod 4). | |
| Apr 13, 2013 at 15:55 | comment | added | Geoff Robinson | @jp: Yes, I mean a Sylow $2$-subgroup of $S_{2^{r}}.$ | |
| Apr 13, 2013 at 14:24 | comment | added | j.p. | @Geoff: Do you mean with your first description just the $2$-Sylow of the symmetric group $S_{2^r}$? It is for finite fields $\mathbb{F}_q$ with $q=3 \bmod 4$ also the $2$-Sylow of $GL_{2^r}(\mathbb{F}_q)$. | |
| Apr 13, 2013 at 12:49 | answer | added | Geoff Robinson | timeline score: 6 | |
| Apr 13, 2013 at 12:31 | comment | added | Geoff Robinson | @Derek: Presumably the group intended is the semidirect product oF elementary Abelian $2$-group of rank $2^{r-1}$ with a Sylow $2$-subgroup of the symmetric group $S_{2^{r-1}},$ or alternatively a Sylow $2$-subgroup of the group of all monomial $2^{r-1} \times 2^{r-1}$ matrices whose only non zero entries are $\pm 1.$ | |
| Apr 13, 2013 at 10:29 | comment | added | Derek Holt | I am not convinced that $H$ is uniquely defined. The wreath product is an associative operation on permutation groups, but not on abstract groups, and $Z_2$ looks like an abstract group rather than a permutatino group. | |
| S Apr 13, 2013 at 10:01 | vote | accept | user27932 | ||
| Apr 14, 2013 at 6:14 | |||||
| Apr 13, 2013 at 10:01 | vote | accept | user27932 | ||
| S Apr 13, 2013 at 10:01 | |||||
| Apr 13, 2013 at 10:01 | vote | accept | user27932 | ||
| Apr 13, 2013 at 10:01 | |||||
| Apr 13, 2013 at 9:33 | answer | added | Stefan Kohl♦ | timeline score: 4 | |
| Apr 13, 2013 at 9:30 | comment | added | Geoff Robinson | You should specify which field(s) you want to work over. | |
| Apr 13, 2013 at 9:18 | answer | added | Boris Novikov | timeline score: 3 | |
| Apr 13, 2013 at 8:08 | history | asked | user27932 | CC BY-SA 3.0 |