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Apr 12, 2013 at 17:44 vote accept GA316
Apr 12, 2013 at 17:24 answer added Steven Landsburg timeline score: 0
Apr 12, 2013 at 14:04 comment added Andreas Blass It's not true in general that non-isomorphic submodules give non-isomorphic quotients. For example, in the abelian group (i.e., $\mathbb Z$-module) $(\mathbb Z/4)\times(\mathbb Z/2)$, the cyclic subgroup $(\mathbb Z/4)\times0$ and the non-cyclic subgroup $(2\mathbb Z/4)\times(\mathbb Z/2)$ both produce quotients that are cyclic of order 2.
Apr 12, 2013 at 13:43 comment added GA316 My intuitive guess is also this same correspondence. but I could not prove that non isomorphic sub modules have non isomorphic quotient modules.. is this very obvious? thanks.
Apr 12, 2013 at 12:49 comment added name $(N \subset M) \leftrightarrow (M / N)$
Apr 12, 2013 at 11:46 history asked GA316 CC BY-SA 3.0