Timeline for At what point would an elementary generalization of Bertrand's Postulate be interesting?
Current License: CC BY-SA 3.0
9 events
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Mar 26, 2016 at 19:35 | comment | added | user9072 | Thank you for the interest in my answer. Note the prime is between $kx$ and $(k+1)x$. So in this case $247800$ and $247800 + 2478$, and $247800+ 11$ is prime. | |
Mar 26, 2016 at 19:06 | comment | added | marh_g | As a check on your equations I set k=100 x=2478 and should therefore expect one prime between 2478 and 2478 + 2478/100 = 2502.78. (for k=100, x must be greater than 2202.65 as detailed by your equations - this condition is met for x=2478). But there are no primes between 2478 and 2502.78. (Though 2503 is prime) Is the domain of x for your answer the positive integers? Then everything checks out. Or as you warned 'up to error'? Appreciate your answer and went through this numerical check to see when a 1% addition to any x>2203 guarantees a prime in what seems to me to be a very short interval. | |
Apr 11, 2013 at 18:41 | vote | accept | Larry Freeman | ||
Apr 11, 2013 at 17:28 | history | edited | user9072 | CC BY-SA 3.0 |
corrected mistyped inequality, added clarification
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Apr 11, 2013 at 17:23 | comment | added | user9072 | @Stefan Kohl: Thank you! Yes this was written in the wrong order. Also, the second is wrong (as I first copied and then modified). I will chanhe the later one now. | |
Apr 11, 2013 at 17:05 | comment | added | Stefan Kohl♦ | @quid: I edited the first inequality, since the left-hand side was larger than the right-hand side. -- Please check! | |
Apr 11, 2013 at 17:04 | history | edited | Stefan Kohl♦ | CC BY-SA 3.0 |
Fixed the first inequality. -- The left-hand side needs to be smaller than the right-hand side.
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Apr 11, 2013 at 16:05 | comment | added | user9072 | Just to be clear regarding the 'up to error': this will work with some explicit value, it just could be a different one if I made an error. | |
Apr 11, 2013 at 15:54 | history | answered | user9072 | CC BY-SA 3.0 |