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Timeline for Genus one fibered links

Current License: CC BY-SA 3.0

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Apr 11, 2013 at 20:42 comment added Ian Agol This works for the Borromean rings, which is a positive genus 1 link, and therefore fibered. Each boundary component is unknotted, and since the linking numbers are zero, the induced framing of the Seifert surface is the longitude. So one may perform Dehn twists around a single boundary component to get an infinite family of fibered genus 1 links (in fact with the same complement).
Apr 11, 2013 at 13:01 comment added Pierre Dehornoy Thanks! The Stallings twist seems a good idea, I will think about it.
Apr 11, 2013 at 12:59 history answered Alex Suciu CC BY-SA 3.0