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Apr 11, 2013 at 11:47 comment added BHZ I am really thankful for your help and your very useful comments.
Apr 11, 2013 at 11:09 comment added Derek Holt In any nilpotent group of class 2, we have $[ab,c]=[a,c][b,c]$ and $[a,b]^{-1} =[b,a]$, so the commutator map is bilinear and alternating, and we get an induced map $G/Z(G) \times G/Z(G) \to Z(G)$. If $|Z(G)|=2$, then $[a^2,b]=1$ for all $a,b$, so $a^2 \in Z(G)$ and $G/Z(G)$ is elementary abelian. So $G$ is extraspecial.
Apr 11, 2013 at 9:27 comment added BHZ Excuse me, the commutator map is from $G/Z(G)\times G/Z(G)$ to $G/Z(G)$ or $Z(G)$? I am sorry, since I am not fammilar with these subjects.
Apr 11, 2013 at 9:04 comment added BHZ Thank you very much for your kindness and your helps. Could you kindly introduce me some references for these subjects for example why $k$ is odd and why $G/Z(G)$ must be elementary abelian.
Apr 11, 2013 at 8:57 vote accept BHZ
Apr 11, 2013 at 8:55 history answered Derek Holt CC BY-SA 3.0