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Apr 9, 2013 at 4:05 vote accept Ricardo Andrade
Apr 8, 2013 at 23:30 comment added Ricardo Andrade Thank you very much for your answer, Allen. I actually wrote an answer using the same idea, and you seem to have posted yours while I was writing mine. :) By the way, a continuous path in the compact-open $C^1$ topology on $\operatorname{Diff}(M)$ also gives a continuous path in the compact-open $C^0$-topology, and such a path is exactly a continuous homotopy $M\times I\to M$. That is another way to prove the claim you require at the end: different $f_n$'s are not in the same component.
Apr 8, 2013 at 22:49 history answered Allen Hatcher CC BY-SA 3.0