Timeline for On the oscillation of the summatory totient about its average
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 8, 2023 at 18:23 | history | edited | Michael Hardy | CC BY-SA 4.0 |
proper spacing
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| Apr 9, 2013 at 6:50 | vote | accept | Kevin Smith | ||
| Apr 8, 2013 at 21:08 | history | edited | Charles Matthews | CC BY-SA 3.0 |
pctn
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| Apr 8, 2013 at 20:52 | answer | added | Peter Humphries | timeline score: 5 | |
| Apr 8, 2013 at 20:39 | comment | added | Kevin Smith | The Mellin transform of $R(x)$, that is. | |
| Apr 8, 2013 at 20:34 | comment | added | Kevin Smith | It is quite lengthy, but the essence is that the integral over a finite interval may be written in terms of a uniformly convergent (for $X>1$) sum over the zeros of $\zeta(s)$. The necessary estimates to justify the limit of the contour are available. The uniform convergence and zero free region enables you to arrive at a contradiction supposing the limit as $X\rightarrow\infty$ is not $0$. More can be probably be said- it appears that the Mellin transform converges on the line $\sigma=1$. | |
| Apr 8, 2013 at 20:10 | comment | added | user9072 | If I may ask, how do you prove this? | |
| Apr 8, 2013 at 18:24 | history | edited | Kevin Smith | CC BY-SA 3.0 |
added 23 characters in body
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| Apr 8, 2013 at 18:19 | history | asked | Kevin Smith | CC BY-SA 3.0 |