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Apr 7, 2019 at 18:16 comment added Federico Poloni This argument only shows that the set of diagonalizable matrices is dense.
Feb 2, 2010 at 23:36 comment added Anweshi @Hanche. That is Sard's theorem.
Jan 24, 2010 at 16:34 comment added Harald Hanche-Olsen You're right, my argument really only proves that the set of non-diagonalizable matrices has empty interior. As a closed set with empty interior can still have positive measure, this doesn't quite clinch the argument in the measure-theoretic sense.
Jan 24, 2010 at 1:31 comment added Anweshi @Harald. It perturbs me that I cannot complete this argument rigorously. Will you be able to help?
Jan 24, 2010 at 0:32 comment added Anweshi The added benefit is that the same argument proves that Zariski closed sets are of measure zero. Of course, I do not know how to write it in detail with the epsilons and deltas, but I am convinced by the heuristics. I am almost tempted to accept this answer over the others!
Jan 23, 2010 at 1:26 history edited Harald Hanche-Olsen CC BY-SA 2.5
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Jan 22, 2010 at 23:15 comment added gowers Or you could simply upper-triangularize your matrix and do the same.
Jan 22, 2010 at 18:52 history answered Harald Hanche-Olsen CC BY-SA 2.5