Timeline for Nilpotency class of a certain finite 2-group
Current License: CC BY-SA 3.0
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Apr 6, 2013 at 17:04 | comment | added | Alireza Abdollahi | @RDK: From where you know $x^{2^d}$ is non-trivial? Note that the relation $x^{2^{d+1}}=1$ cannot solely imply that the order of $x$ is $2^{d+1}$. The answer of Derek Holt can help you to understand the main difficulty. | |
Apr 6, 2013 at 6:44 | history | answered | Soluble | CC BY-SA 3.0 |