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Jan 23, 2010 at 12:31 comment added Pete L. Clark Also recall the existence of space-filling curves over finite fields. Anyway, I think by now you take my point...
Jan 23, 2010 at 12:28 comment added Pete L. Clark ... c.f. Exercise 21 of math.uga.edu/~pete/8320homework1.pdf
Jan 23, 2010 at 12:26 comment added Pete L. Clark @KB: Here I meant the Zariski topology on $\mathbb{A}^n(k)$ -- I don't want to suggest scheme theory as a prerequisite for linear algebra! -- so that this is the discrete topology iff $k$ is finite.
Jan 23, 2010 at 12:19 comment added Kevin Buzzard Pete: being a closed subset of A^n which isn't A^n is still a powerful statement when k is finite, because, as you well know, affine n-space over a finite field is still an infinite set. I once had to think twice about the following: "proper + quasi-finite implies finite, but projective 1-space over a finite field is proper and quasi-finite---umm---aah I see the point".
Jan 23, 2010 at 9:57 history edited Pete L. Clark CC BY-SA 2.5
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Jan 22, 2010 at 18:35 history edited Pete L. Clark CC BY-SA 2.5
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Jan 22, 2010 at 18:11 history answered Pete L. Clark CC BY-SA 2.5