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Timeline for Categories of recursive functions

Current License: CC BY-SA 3.0

14 events
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Apr 23, 2020 at 20:41 answer added Todd Trimble timeline score: 8
Apr 10, 2013 at 18:57 answer added Paul Taylor timeline score: 6
Apr 9, 2013 at 16:08 vote accept Wouter Stekelenburg
Apr 7, 2013 at 15:28 answer added Paul Taylor timeline score: 33
Apr 5, 2013 at 7:04 comment added Wouter Stekelenburg @Francois: I assume regular categories have finite limits. The definition of NNO is in the question, but 'parametrized' sounds like a good description.
Apr 4, 2013 at 16:48 comment added François G. Dorais So for 2, you're just looking at a regular category with finite limits (or just products?) and a parametrized nno? (Disjoint coproducts too?)
Apr 4, 2013 at 16:46 comment added François G. Dorais No, a nonstandard Gödel code doesn't give a proof in any reasonable sense.
Apr 4, 2013 at 16:45 comment added Noah Schweber @Wouter: If I understand what you're asking, the answer is no: assuming $PA$ is consistent, there are models of $PA$ (hence, satisfying $0\not=1$) which contain internal "proofs" that 0=1.
Apr 4, 2013 at 16:43 history edited Wouter Stekelenburg CC BY-SA 3.0
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Apr 4, 2013 at 16:42 comment added Wouter Stekelenburg @Francois: in a regular category, a partial function $X\rightharpoonup Y$ is an isomorphism class of spans $(m:Z\to X, f:Z\to Y)$ where $m$ is monic. If a non standard model forces that $0=1$ is provable, doesn't it automatically force $0=1$?
Apr 4, 2013 at 15:18 comment added François G. Dorais Unless you insist on well-pointed categories, there are usually no major issues using intensional equality instead of extensional equality.
Apr 4, 2013 at 15:04 comment added François G. Dorais I think 1 is also sensitive to formalization, but not as much. The problem is not that functions can be omitted but that they can be accidentally identified. For example, there is a p.r. function $c$ such that $c(x) = 0$ unless $x$ is a Gödel code of a PA-proof of $0=1$, in which case $c(x)=1$. In the standard model, $c$ is the identically $0$ function. If these are actually the same in your category, then it is not initial since there are models where $c$ is not identically $0$. However, this is can be fixed using intensional equality instead of extensional equality.
Apr 4, 2013 at 14:55 comment added François G. Dorais I'm curious how you formalize partial functions in 2.
Apr 4, 2013 at 13:37 history asked Wouter Stekelenburg CC BY-SA 3.0