Skip to main content
15 events
when toggle format what by license comment
Apr 15, 2013 at 19:28 comment added HJRW The proof was written up by Steve D in this MO answer: mathoverflow.net/questions/9628/… . Roger Alperin wrote up an elementary proof in his paper 'An elementary account of Selberg's lemma'.
Apr 15, 2013 at 16:13 comment added Mikhail Katz Do you have a reference where your remarks on Jacobson rings and linear groups are treated in more detail?
Apr 15, 2013 at 15:17 comment added HJRW Re: your later comments, no, I don't think that Hempel didn't believe Thurston; rather, Thurston characteristically doesn't give all the details. Hempel's paper shows how to deduce residual finiteness from geometrization.
Apr 15, 2013 at 15:12 comment added HJRW In response to your first comment, no, it's not significantly harder. In any Jacobson ring you have enough maximal ideals to prove residual finiteness. Malcev observed this in the 40s; the upshot is that any fg linear group is residually finite.
Apr 15, 2013 at 14:30 comment added Mikhail Katz Hempel, John Residual finiteness for 3 -manifolds. Combinatorial group theory and topology (Alta, Utah, 1984), 379–396, Ann. of Math. Stud., 111, Princeton Univ. Press, Princeton, NJ, 1987 proved this again in the Haken case. I guess he wasn't convinced by Thurston. Does anybody know the history of this?
Apr 15, 2013 at 14:23 comment added Mikhail Katz I see that the paper Thurston, William P. Three-dimensional manifolds, Kleinian groups and hyperbolic geometry. Bull. Amer. Math. Soc. (N.S.) 6 (1982), no. 3, 357–381 proves RF in the Haken case.
Apr 15, 2013 at 14:17 comment added Mikhail Katz Exactly my point. Congruence subgroups provide both lower bounds for systole and proof of RF for arithmetic manifolds. I don't remember if RF is also true for nonarithmetic ones, but I assume it is harder.
Apr 15, 2013 at 14:12 comment added HJRW One (usually) proves residual finiteness of hyperbolic 3-manifolds using congruence quotients, so this is just the same thing.
Apr 15, 2013 at 13:44 comment added Mikhail Katz I didn't find the word "congruence subgroup" on this page, so I thought I would comment that using congruence subgroups may be more elementary than appealing to residual finiteness of 3-manifolds.
Apr 4, 2013 at 4:40 vote accept Bidyut Sanki
Apr 4, 2013 at 4:40
Apr 3, 2013 at 14:51 history edited Autumn Kent CC BY-SA 3.0
added 86 characters in body
Apr 3, 2013 at 13:59 comment added Misha Richard, maybe you should also mention that you use normal finite index subgroups, this will take care of the base point business.
Apr 3, 2013 at 13:35 comment added Autumn Kent Yes, I should've said that. Thanks, Misha.
Apr 3, 2013 at 13:32 comment added Misha Ditto for all compact hyperbolic manifolds.
Apr 3, 2013 at 11:56 history answered Autumn Kent CC BY-SA 3.0