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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Apr 3, 2013 at 15:18 vote accept Barry Cipra
Apr 3, 2013 at 1:16 answer added Siksek timeline score: 13
Apr 2, 2013 at 21:57 answer added Mike Bennett timeline score: 4
Apr 2, 2013 at 17:47 comment added user30035 [I'm not suggesting this helps, I'm just answering the implicit question in your last sentence.]
Apr 2, 2013 at 17:46 comment added user30035 $a$ is determined by $n$ because $a$ is the $5$-adic valuation of $2^n+1$. More precisely, $2$ is a primitive root mod $5^t$ for all $t\geq1$ so $5^t$ divides $2^n+1$ iff $2^n=-1=2^{2.5^{t-1}}$ mod $5^t$ iff $n$ is congruent to $2.5^{t-1}$ mod $4.5^{t-1}$, so $a$ is the largest value of $t$ for which that's true. Basically $n$ has to be 2 mod 4 for $a>0$ and then $a$ is one plus the number of times 5 goes into $n$, if I got it right.
Apr 2, 2013 at 16:06 history asked Barry Cipra CC BY-SA 3.0