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Apr 1, 2013 at 12:33 comment added Jérémy Blanc @ leffe: yes, this is exactly this.
Apr 1, 2013 at 12:32 comment added Jérémy Blanc As a comment, another example in dimension $2$ (which is almost the same as the one of Francesco): let $X\to \mathbb{P}^2$ be the double covering ramified over a smooth quartic. Then, $X$ is a smooth del Pezzo surface of degree $2$ and the pull-back of an hyperplane section is the anticanonical divisor of $X$, which is ample but not very ample (the morphism associated is exactly the double covering).
Apr 1, 2013 at 12:31 comment added leffe Thanks Francesco! In general the pullback of a very ample divisor will only be ample, so it would be necessary to pass to a power to have something very ample. Does it mean that if I consider a suitable multiple of my embedding $X \hookrightarrow \mathbb{P}^N$ and I replace hyperplane sections by hypersurface sections the condition I want will be verified?
Apr 1, 2013 at 12:12 history answered Francesco Polizzi CC BY-SA 3.0