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Apr 1, 2013 at 4:01 comment added Douglas Zare I guess I should have included $\omega, 2\omega, 4\omega, ... \omega^2, 2\omega^2, ...$ among the primes in case you are considering well-founded games with infinitely many options.
Apr 1, 2013 at 3:41 history edited Douglas Zare CC BY-SA 3.0
added a little more about Nim
Apr 1, 2013 at 1:48 comment added Mark Wildon Just to expand on the final line: in the game $G + \star n$, if the first player plays to $\star m$ in $G$ where $m < n$, then the second player can play in $\star n$ to give $\star m + \star m = 0$; if the first player plays to $\star m'$ in $\star n$ where $m' < n$ then the second player can play in $G$ to $\star m'$ to give $\star m' + \star m' = 0$. (We know that $\star m'$ is an option of $G$ because $n$ is the minimum excluded option.) Hence $G + \star n = 0$ and $G = \star n$.
Mar 31, 2013 at 23:25 history answered Douglas Zare CC BY-SA 3.0