Skip to main content
5 events
when toggle format what by license comment
Apr 27, 2013 at 1:42 vote accept Joshua Seaton
Mar 31, 2013 at 19:53 answer added Geoffroy Horel timeline score: 4
Mar 31, 2013 at 14:14 comment added Joshua Seaton $S \times X \to X$ gives rise to $B(S \times X ) \to BX$. Unless we know that $BS$ is locally compact, in which case the natural map $B(S \times X) \to BS \times BX$ is a homeomorphism, how do we get a map $BS \times BX \to BX$?/
Mar 31, 2013 at 0:26 comment added Geoffroy Horel $BS$ acts on $BX$, therefore you have an action map $H_0(BS)\otimes H_p(BX)\to H_p(BX)$. $H_0(BS)=\mathbb{Z}[\pi_0(BS)]$, therefore you have an action of the group algebra $\mathbb{Z}[\pi_0(BS)]$ on $H_p(BX)$ or equivalently an action of the group $\pi_0(S)$ on $H_p(BX)$.
Mar 30, 2013 at 2:25 history asked Joshua Seaton CC BY-SA 3.0