Timeline for Dual of $\mathbb Z^I$ for uncountable $I$
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Apr 6, 2023 at 11:02 | comment | added | The Amplitwist | Reposting the link mentioned in a previous comment so that it appears in the "Linked" questions list: Is it true that, as $\Bbb Z$-modules, the polynomial ring and the power series ring over integers are dual to each other? | |
| S Apr 2, 2019 at 17:41 | history | suggested | user26857 | CC BY-SA 4.0 |
impoved format
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| Apr 2, 2019 at 17:11 | review | Suggested edits | |||
| S Apr 2, 2019 at 17:41 | |||||
| Mar 2, 2015 at 1:02 | vote | accept | Martin Brandenburg | ||
| May 29, 2013 at 0:57 | comment | added | Ralph | To address the question in the title: The $\mathbb{Z}$-dual of $\mathbb{Z}^I$ is the free abelian group whose rank equals the cardinality of the set $D$ of all countably complete ultrafilters on $I$. Moreover, $|I| \le |D|$ and if the cardinality of $I$ is less than the first measurable cardinal, then $|I|=|D|$. For references see my answer to this question: mathoverflow.net/questions/132073/… | |
| May 28, 2013 at 22:00 | answer | added | Todd Trimble | timeline score: 9 | |
| Jan 22, 2010 at 2:25 | vote | accept | Martin Brandenburg | ||
| Mar 2, 2015 at 1:02 | |||||
| Jan 22, 2010 at 2:23 | vote | accept | Martin Brandenburg | ||
| Jan 22, 2010 at 2:25 | |||||
| Jan 22, 2010 at 0:57 | history | edited | Mariano Suárez-Álvarez | CC BY-SA 2.5 |
Fix the reference and provide MR link
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| Jan 22, 2010 at 0:15 | history | edited | Anweshi |
edited tags
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| Jan 22, 2010 at 0:14 | comment | added | Anweshi | Related qn, when I is countable .. mathoverflow.net/questions/10239 | |
| Jan 22, 2010 at 0:04 | history | asked | Martin Brandenburg | CC BY-SA 2.5 |