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fix markup and a typo
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Emil Jeřábek
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Or, very simply stated, given the finite set $S$ = {$a_1, ... , a_k$}$S = \{a_1, \dots , a_k\}$, consider the diophantine equation: $$(n-a_1)...(n-a_n)=0$$.$$(n-a_1)\dots(n-a_k)=0.$$ EDIT: Then we can write S as {$ \ n \ | \ \exists x : (n-a_1)...(n-a_k)=0$ }$\{ \ n \ | \ \exists x : (n-a_1)\dots(n-a_k)=0\ \}$. (Thanks David)

Or, very simply stated, given the finite set $S$ = {$a_1, ... , a_k$}, consider the diophantine equation: $$(n-a_1)...(n-a_n)=0$$. EDIT: Then we can write S as {$ \ n \ | \ \exists x : (n-a_1)...(n-a_k)=0$ }. (Thanks David)

Or, very simply stated, given the finite set $S = \{a_1, \dots , a_k\}$, consider the diophantine equation: $$(n-a_1)\dots(n-a_k)=0.$$ EDIT: Then we can write S as $\{ \ n \ | \ \exists x : (n-a_1)\dots(n-a_k)=0\ \}$. (Thanks David)

added 79 characters in body; added 15 characters in body
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Or, very simply stated, given the finite set $S$ = {$a_1, ... , a_n$$a_1, ... , a_k$}, consider the diophantine equation: $$(x-a_1)...(x-a_n)=0$$$$(n-a_1)...(n-a_n)=0$$. EDIT: Then we can write S as {$ \ n \ | \ \exists x : (n-a_1)...(n-a_k)=0$ }. (Thanks David)

Or, very simply stated, given the finite set $S$ = {$a_1, ... , a_n$}, consider the diophantine equation: $$(x-a_1)...(x-a_n)=0$$.

Or, very simply stated, given the finite set $S$ = {$a_1, ... , a_k$}, consider the diophantine equation: $$(n-a_1)...(n-a_n)=0$$. EDIT: Then we can write S as {$ \ n \ | \ \exists x : (n-a_1)...(n-a_k)=0$ }. (Thanks David)

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Or, very simply stated, given the finite set $S$ = {$a_1, ... , a_n$}, consider the diophantine equation: $$(x-a_1)...(x-a_n)=0$$.