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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jul 28, 2014 at 16:28 comment added darij grinberg This proof can be made even simpler: If the determinant of the big matrix were $0$, then there would be a nontrivial $\mathbb{R}$-linear combination of its columns that would equal $0$. This immediately means that a nontrivial exponential polynomial with $n$ terms has at least $n$ distinct real roots; this completes the proof, with no induction needed. (Combined with the correct part of my answer, this yields that the determinant is positive.)
Mar 27, 2013 at 22:16 comment added Noam D. Elkies Thanks. We also need that the coefficients of this exponential polynomial are not all zero; but each coefficient is an order $n-1$ determinant of the same type, so we can frame this as an argument by induction, and then at the $n-1$ step we showed that all of the coefficients are nonzero, so we're done.
Mar 27, 2013 at 20:36 history answered Todd Trimble CC BY-SA 3.0