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Timeline for Non-abelian divisible groups

Current License: CC BY-SA 3.0

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Mar 26, 2013 at 3:56 comment added Shripad Yes Misha, that will also do. But I thought that the knowledge of (even existence of) Riemannian metric is difficult than the basic cohomology theory of compact manifolds. :-).
Mar 21, 2013 at 16:58 comment added Misha You do not need any of these, just the fact that exponential map for every compact Lie group $G$ equals Riemannian exponential map for the bi-invariant Riemannian metric on $G$.
Mar 21, 2013 at 11:31 history answered Shripad CC BY-SA 3.0