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Mar 20, 2013 at 7:41 vote accept Ferpect
Mar 20, 2013 at 7:41
Mar 19, 2013 at 20:05 comment added Suvrit Sorry, there was an obvious typo in there; of course, I mean hermitian positive def. matrices. Fixed now.
Mar 19, 2013 at 20:04 history edited Suvrit CC BY-SA 3.0
fixed typo in the counterexample
Mar 19, 2013 at 17:36 comment added Ferpect Sorry, I don't get your answer... 1) X is not symmetric, let alone positive definite, My question regarded exclusively PD matrices. 2) if with $f$ you mean the functional $f(A)=\|A^{-1}\|_1$, then $f(Z)=3.46 < 3.5 = \frac{1}{2} (f(X)+f(Y))$ which does not violate convexity
Mar 19, 2013 at 16:47 history answered Suvrit CC BY-SA 3.0