Timeline for Is the set of the absolutely continuous functions a Borel set of the space of the continuous functions?
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Feb 25, 2014 at 21:21 | answer | added | Nate Eldredge | timeline score: 2 | |
| Feb 25, 2014 at 15:32 | history | edited | user9072 | CC BY-SA 3.0 |
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| Mar 22, 2013 at 20:00 | answer | added | Etienne | timeline score: 4 | |
| Mar 22, 2013 at 15:49 | comment | added | Bill Johnson | en.wikipedia.org/wiki/Absolute_continuity | |
| Mar 21, 2013 at 19:56 | comment | added | Theluze | Indeed, any function of $C$ is uniformly continuous but what's the link with the absolute continuity ? | |
| Mar 20, 2013 at 9:29 | vote | accept | Theluze | ||
| Mar 19, 2013 at 19:16 | comment | added | Bill Johnson | Let $E_{n,m}$ be the set of all $f$ in $C[0,1]$ s.t. whenever $|x-y| \le 1/m$ we have $|f(x)-f(y)|\le 1/n$ and consider $\cap_n\cup_m E_{n,m}$. $$ $$ In other words, just use the definition of absolute continuity. | |
| Mar 19, 2013 at 17:30 | vote | accept | Theluze | ||
| Mar 19, 2013 at 18:21 | |||||
| Mar 19, 2013 at 12:45 | answer | added | marcoromito | timeline score: 3 | |
| Mar 19, 2013 at 11:17 | history | edited | Theluze | CC BY-SA 3.0 |
edited title; edited title
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| Mar 19, 2013 at 10:58 | history | edited | Theluze |
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| Mar 19, 2013 at 10:49 | history | asked | Theluze | CC BY-SA 3.0 |