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Jul 10, 2016 at 14:00 comment added Tim Campion A reference for the fact that every monadic category over $\mathsf{Set}$ is cocomplete can be found on the nlab, Corollary 1. Alternatively, use the observation of Linton (discussed on the same page, Theorem 1) that if $C$ is cocomplete and $C^T$ has reflexive coequalizers then $C^T$ is cocomplete. After all, compact spaces are closed under quotients, and Hausorffification is another quotient, so compact Hausdorff spaces have all coequalizers, formed by taking the coequalizer and Hausdorffifying.
Mar 21, 2013 at 3:43 vote accept Ricardo Andrade
Mar 19, 2013 at 9:26 comment added Ricardo Andrade @Chris: No problem. Thanks again. Also, sorry for the simple question.
Mar 19, 2013 at 9:23 history edited Chris Schommer-Pries CC BY-SA 3.0
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Mar 19, 2013 at 9:21 comment added Chris Schommer-Pries @Ricardo: Yes I miss typed the formula the first time. It is supposed to be an upside down parabola which goes through (0,0), (0.5, 0.5) and (1, 0). I think it is fixed now. As you increase the factor 2 the behavior changes and becomes chaotic. see physics.udel.edu/~jim/PHYS460_660_13S/oscillations&chaos/… This must mean quotients become really really bad non-Hausdorff spaces.
Mar 19, 2013 at 9:16 comment added Ricardo Andrade @Chris: It seems you meant $t\mapsto t^2$ or something like that. In any case, the idea stands, and I see that my conditions are way too strict. That certainly settles the question as I stated it. Thank you very much.
Mar 19, 2013 at 9:06 history answered Chris Schommer-Pries CC BY-SA 3.0