Timeline for Can we generalize the result of Urysohn's lemma to countable collection of pairwise disjoint closed subsets of a normal space..?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 19, 2013 at 12:00 | vote | accept | Janson A.J | ||
| Mar 18, 2013 at 14:16 | answer | added | Ramiro de la Vega | timeline score: 0 | |
| Mar 17, 2013 at 19:48 | comment | added | Joseph Van Name | I wanted to see if Janson A.J. would have edited the question to make it look more like a research question. For instance, he could have replaced "pairwise disjoint" with something like "locally discrete". | |
| Mar 17, 2013 at 19:39 | comment | added | David White | Hmm, seems you guys beat me to the punch. But why not just make your comments actual answers? | |
| Mar 17, 2013 at 19:36 | answer | added | David White | timeline score: 2 | |
| Mar 17, 2013 at 19:29 | comment | added | user23860 | No, take $A_n=\{1/n\}\subset \mathbb{R}$. | |
| Mar 17, 2013 at 19:28 | comment | added | Joseph Van Name | You will need more than just the sets being pairwise disjoint. For instance, if $X$ is the one-point compactification on $\mathbb{N}$, $A_{0}=\\{\infty\\}$ and $A_{n}=\{n\}$ for all $n$, then there is no continuous real-valued function $f$ on $X$ with $f=n$ on $A_{n}$ for all $n$. | |
| Mar 17, 2013 at 19:17 | history | asked | Janson A.J | CC BY-SA 3.0 |