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Mar 16, 2013 at 12:21 comment added mjb86 Yes, that is what one would think they do. But they are writing "the continuous spectrum of $L$ [which still has the $f$ and $g$] is the same, if $f$, $g$ decay sufficiently fast". What sense does that statement make if $f=g=0$?
Mar 15, 2013 at 19:12 history answered Carlo Beenakker CC BY-SA 3.0