Timeline for What goes wrong for the Sobolev embeddings at $k=n/p$?
Current License: CC BY-SA 3.0
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| Aug 15, 2023 at 1:01 | comment | added | AmorFati | Thank you for this very insightful answer. Can I just ask how one pinpoints $\log \log(1+1/|x|)$ exactly from what you have said. I understand that $\sum_{i=1}^k 1/i \sim \log \log(2^k)$, but why do we specifically choose $1+1/|x|$? | |
| May 3, 2013 at 14:57 | vote | accept | Chris Gerig | ||
| Mar 12, 2013 at 18:14 | history | edited | Connor Mooney | CC BY-SA 3.0 |
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| Mar 12, 2013 at 18:04 | history | edited | Connor Mooney | CC BY-SA 3.0 |
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| Mar 12, 2013 at 16:59 | history | answered | Connor Mooney | CC BY-SA 3.0 |