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Mar 12, 2013 at 7:22 vote accept Jochen Wengenroth
Mar 12, 2013 at 7:17 comment added Jochen Wengenroth Your way to prove the identity is certainly better.
Mar 12, 2013 at 4:48 answer added Michael Albert timeline score: 4
Mar 12, 2013 at 2:52 comment added Michael Albert I'm not sure if the $z_{2n}$ identity is correctly explained (it is correct) -- it seems rather to follow from the fact that in general the sum of consecutive even and odd terms in $z_{2n}$ is equal to $(1 + e^x)$ times a single term contributing to $z_n$ rather than a matching between the first half and the second half. But perhaps I'm missing something.
Mar 11, 2013 at 23:04 comment added Gerry Myerson The m.se reference is to math.stackexchange.com/questions/324496/binary-expansions where there is an open bounty on the question.
Mar 11, 2013 at 15:32 history edited Jochen Wengenroth CC BY-SA 3.0
correced $n/2-1$ to $n/2 +1$
Mar 11, 2013 at 7:19 history asked Jochen Wengenroth CC BY-SA 3.0