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Added a link to a table with more extensive numerical data.
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Stefan Kohl
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Barry Cipra has already computed the first few values. The next couple of numbers $p_n$ are

$13 = 5 \cdot 11 - 2 \cdot 3 \cdot 7$,

$17 = 2 \cdot 7 \cdot 13 - 3 \cdot 5 \cdot 11$,

$19 = 2^2 \cdot 3 \cdot 5 \cdot 17 - 7 \cdot 11 \cdot 13 $,

$23 = 7 \cdot 11 \cdot 17^2 - 2 \cdot 3^2 \cdot 5 \cdot 13 \cdot 19$,

$29 = 3 \cdot 11 \cdot 13^2 \cdot 19 \cdot 23 - 2^{12} \cdot 5 \cdot 7 \cdot 17$.

I don't find such expression for 31 in numbers $\leq 10^{12}$.

The smallest I find is $47 = 3 \cdot 7 \cdot 19^2 \cdot 23 \cdot 29 - 2^5 \cdot 5 \cdot 11 \cdot 13^2 \cdot 17$.

If the abc conjecture is true, there are at most finitely many ways to express the $n$-th prime as a difference of coprime numbers which are divisible only by the first $n-1$ primes.

Addendum: For a more extensive table, see http://www.fermatquotient.com/DiverseMinimas/S=M-N_min (found by Google'ing for the numbers obtained above). The data supports the assumption that the OP's assertion is unlikely to be true.

Barry Cipra has already computed the first few values. The next couple of numbers $p_n$ are

$13 = 5 \cdot 11 - 2 \cdot 3 \cdot 7$,

$17 = 2 \cdot 7 \cdot 13 - 3 \cdot 5 \cdot 11$,

$19 = 2^2 \cdot 3 \cdot 5 \cdot 17 - 7 \cdot 11 \cdot 13 $,

$23 = 7 \cdot 11 \cdot 17^2 - 2 \cdot 3^2 \cdot 5 \cdot 13 \cdot 19$,

$29 = 3 \cdot 11 \cdot 13^2 \cdot 19 \cdot 23 - 2^{12} \cdot 5 \cdot 7 \cdot 17$.

I don't find such expression for 31 in numbers $\leq 10^{12}$.

The smallest I find is $47 = 3 \cdot 7 \cdot 19^2 \cdot 23 \cdot 29 - 2^5 \cdot 5 \cdot 11 \cdot 13^2 \cdot 17$.

If the abc conjecture is true, there are at most finitely many ways to express the $n$-th prime as a difference of coprime numbers which are divisible only by the first $n-1$ primes.

Barry Cipra has already computed the first few values. The next couple of numbers $p_n$ are

$13 = 5 \cdot 11 - 2 \cdot 3 \cdot 7$,

$17 = 2 \cdot 7 \cdot 13 - 3 \cdot 5 \cdot 11$,

$19 = 2^2 \cdot 3 \cdot 5 \cdot 17 - 7 \cdot 11 \cdot 13 $,

$23 = 7 \cdot 11 \cdot 17^2 - 2 \cdot 3^2 \cdot 5 \cdot 13 \cdot 19$,

$29 = 3 \cdot 11 \cdot 13^2 \cdot 19 \cdot 23 - 2^{12} \cdot 5 \cdot 7 \cdot 17$.

I don't find such expression for 31 in numbers $\leq 10^{12}$.

The smallest I find is $47 = 3 \cdot 7 \cdot 19^2 \cdot 23 \cdot 29 - 2^5 \cdot 5 \cdot 11 \cdot 13^2 \cdot 17$.

If the abc conjecture is true, there are at most finitely many ways to express the $n$-th prime as a difference of coprime numbers which are divisible only by the first $n-1$ primes.

Addendum: For a more extensive table, see http://www.fermatquotient.com/DiverseMinimas/S=M-N_min (found by Google'ing for the numbers obtained above). The data supports the assumption that the OP's assertion is unlikely to be true.

Source Link
Stefan Kohl
  • 19.6k
  • 21
  • 75
  • 137

Barry Cipra has already computed the first few values. The next couple of numbers $p_n$ are

$13 = 5 \cdot 11 - 2 \cdot 3 \cdot 7$,

$17 = 2 \cdot 7 \cdot 13 - 3 \cdot 5 \cdot 11$,

$19 = 2^2 \cdot 3 \cdot 5 \cdot 17 - 7 \cdot 11 \cdot 13 $,

$23 = 7 \cdot 11 \cdot 17^2 - 2 \cdot 3^2 \cdot 5 \cdot 13 \cdot 19$,

$29 = 3 \cdot 11 \cdot 13^2 \cdot 19 \cdot 23 - 2^{12} \cdot 5 \cdot 7 \cdot 17$.

I don't find such expression for 31 in numbers $\leq 10^{12}$.

The smallest I find is $47 = 3 \cdot 7 \cdot 19^2 \cdot 23 \cdot 29 - 2^5 \cdot 5 \cdot 11 \cdot 13^2 \cdot 17$.

If the abc conjecture is true, there are at most finitely many ways to express the $n$-th prime as a difference of coprime numbers which are divisible only by the first $n-1$ primes.