Timeline for Outer automorphisms of Borel subgroup
Current License: CC BY-SA 3.0
6 events
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| Mar 6, 2013 at 22:46 | comment | added | Venkataramana | Dmitri: you are right. This does give the automorphism $\sigma$. | |
| Mar 6, 2013 at 20:09 | comment | added | Dmitri Nikshych | Thanks, Aakumadula ! Probably one can deduce that $\theta$ (modulo an inner automorphism) respects root subgroups by using that normal abelian subgroups of $B$ are in bijection with positive roots (at least for the type $A_n$). In particular, maximal normal abelian subgroups of $B$ correspond to simple roots. The automorphism $\sigma'$ of $B$ given by composition of taking transpose w.r.t (1n) -- (n1) diagonal and taking the inverse. Does this coincide with your $\sigma$? (it corresponds to the symmetry of the $A_n$ Dynkin diagram). | |
| Mar 6, 2013 at 5:59 | history | edited | Venkataramana | CC BY-SA 3.0 |
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| Mar 6, 2013 at 5:22 | history | edited | Venkataramana | CC BY-SA 3.0 |
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| Mar 6, 2013 at 4:48 | history | edited | Venkataramana | CC BY-SA 3.0 |
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| Mar 6, 2013 at 4:14 | history | answered | Venkataramana | CC BY-SA 3.0 |