Timeline for Is there a rigid curve in a product of complex manifolds?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Mar 4, 2013 at 20:41 | comment | added | Atsushi Kanazawa | I see. The argument works only for $\mathbb{P}^1$. Thanks. | |
| Mar 4, 2013 at 18:51 | comment | added | Tom Graber | If you have a map from P^1, to the product, then you have one to each factor separately. If one of those maps is constant, then you just deform the map by moving the point. If both maps are nonconstant, then you get a copy of $P^1 \times P^1$ in the product, where your curve lives, and so it deforms inside that surface. | |
| Mar 4, 2013 at 18:18 | comment | added | Atsushi Kanazawa | Hi Tom. How do you see the assertion for rational curves? Thanks. | |
| Mar 4, 2013 at 17:03 | comment | added | Tom Graber | This would be true if you were asking about rational curves. | |
| Mar 4, 2013 at 11:26 | history | edited | Francesco Polizzi |
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| Mar 4, 2013 at 11:05 | answer | added | Francesco Polizzi | timeline score: 12 | |
| Mar 4, 2013 at 10:22 | history | asked | Thom | CC BY-SA 3.0 |