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Feb 27, 2013 at 13:34 comment added S. Carnahan You may find some information in Kac-Raina's Bombay lectures.
Feb 27, 2013 at 7:44 comment added José Figueroa-O'Farrill (cont'd) So what exactly do you need the explicit submodule for? If you want to gain intuition about this construction, perhaps you should look at how it works with a simple Lie algebra of small dimension, such as $\mathfrak{su}(2)$.
Feb 27, 2013 at 7:43 comment added José Figueroa-O'Farrill The submodule in question might depend on the actual affine algebra that you are dealing with and in the actual highest weight. I am not sure that you can be very explicit in the general case. Already for finite simple Lie algebras, where the same construction applies, I am not aware of any explicit formula in general, but others will surely correct me if I'm wrong. Having said that, it is clear that the Verma module will have a maximal proper submodule and that the quotient, by definition, will be irreducible and of highest weight.
Feb 27, 2013 at 5:44 history asked Sven Cattell CC BY-SA 3.0