Timeline for Find a "natural" group that contains the quotient of the infinite symmetric group by the alternating subgroup
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Jul 29, 2019 at 8:02 | history | edited | Martin Sleziak | CC BY-SA 4.0 |
added eudml link
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| Dec 20, 2018 at 23:59 | comment | added | YCor | ... and the weaker fact that there is no nontrivial homomorphism from $S_\infty$ to $\mathbf{Z}/2\mathbf{Z}$ was initially proved by Vitali in 1915. Up to my knowledge, this is the first explicit appearance of the infinite symmetric group. | |
| Feb 10, 2018 at 22:08 | comment | added | YCor | The "Schreier-Ulam" theorem was initially proved by Onofri (1929) and then rediscovered by Schreier-Ulam (1933), the first reference being widely forgotten. Details: math.stackexchange.com/a/2645097/35400 | |
| Jan 19, 2010 at 17:45 | comment | added | Martin Brandenburg | ok I should have written that I knew this result (I used it in my claim that Z/2 does not work), but you have made it clear that my problem is really to get a good description of $S_\infty / \mathfrak{a}_\infty$ - is there a good one? | |
| Jan 19, 2010 at 13:35 | history | edited | Pete L. Clark | CC BY-SA 2.5 |
added 771 characters in body
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| Jan 19, 2010 at 13:04 | comment | added | Kevin Buzzard | @Pete: ouch. Doesn't this mean that my answer is the best that Martin will get?? The kernel of his sign map will be a non-trivial proper normal subgroup, and it can't contain a transposition, so it must be my A (your a_infty). | |
| Jan 19, 2010 at 12:57 | history | answered | Pete L. Clark | CC BY-SA 2.5 |