Timeline for Find a "natural" group that contains the quotient of the infinite symmetric group by the alternating subgroup
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 20, 2010 at 10:28 | comment | added | Kevin Buzzard | FWIW today I'm wearing fashionablygeek.com/wp-content/uploads/2007/12/usheep-shirt.jpg in olive green. | |
| Jan 20, 2010 at 4:12 | comment | added | Pete L. Clark | "...(and I have no reason to believe it's not)" Thanks for the ringing endorsement, KB. I have no reason to believe that you're not wearing a "Rehab Is For Quitters" T-shirt and parachute pants...no reason at all. | |
| Jan 19, 2010 at 13:05 | comment | added | Kevin Buzzard | If Pete's statement of Schreier-Ulam is correct (and I have no reason to believe it's not) then S_\infty/A has no non-trivial quotients which are non-trivial on z. So it looks like this "answer" is the best you're going to get, modulo finding a nicer way of defining the quotient space. | |
| Jan 19, 2010 at 11:11 | history | answered | Kevin Buzzard | CC BY-SA 2.5 |
