Timeline for Decomposing maximal compact subgroups of SO(n,1)
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Oct 27, 2017 at 19:09 | answer | added | jorge vargas | timeline score: 1 | |
| Apr 12, 2013 at 7:17 | answer | added | D.Kleinbock | timeline score: 1 | |
| Feb 22, 2013 at 5:35 | comment | added | Davis | @Misha. Thank you. Indeed, $\mathfrak h$ is not a Lie Algebra. For my purpose it is enough to consider the group generated by $exp(\mathfrak h)$. In this case, what can I say about the cosets of $K/HM$? | |
| Feb 22, 2013 at 5:30 | history | edited | Davis | CC BY-SA 3.0 |
deleted 1 characters in body; deleted 47 characters in body
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| Feb 22, 2013 at 4:51 | comment | added | Venkataramana | this is independent of what $\mathfrak h$ may be. As Misha says, $\mathfrak h$ is not a Lie algebra. | |
| Feb 22, 2013 at 4:27 | comment | added | Venkataramana | the issue is one of connected components; so one must be careful about the groups $K$ and $M$. your $K$ is not $SO(n)$ but $O(n)$. Your $M$ is not $SO(n-1)$ but $O(n-1)$. In this case $K/HM$ is connected. | |
| Feb 22, 2013 at 4:18 | comment | added | Misha | ${\mathfrak h}$ is not a Lie algebra, what do you mean by $H$? | |
| Feb 22, 2013 at 2:48 | history | asked | Davis | CC BY-SA 3.0 |