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Feb 21, 2013 at 21:57 comment added user9072 You are welcome! It was interesting to think about this for me. Yes one might wish to avoid knowing the divisors. But at least the improvement to only go to (|F|-1)/2 could always be done.
Feb 21, 2013 at 10:45 comment added Matthieu Romagny On the other hand, optimizing implies knowing some arithmetic of $p-1$ (e.g. its decomposition into primes) and then it gets complicated. By the way, thanks quid for your participation!
Feb 20, 2013 at 18:19 comment added user9072 Yes, I agree. This is about what I had in mind when saying it is not optimized.
Feb 20, 2013 at 15:31 comment added Matthieu Romagny ... and in particular $d\le \lfloor (p-1)/2 \rfloor$.
Feb 20, 2013 at 15:29 comment added Matthieu Romagny I came to a similar formula after discussions with Pascal Boyer. And if I have it right, in the second product you can restrict to $d$'s dividing $|F|-1$.
Feb 19, 2013 at 23:13 history edited user9072 CC BY-SA 3.0
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Feb 19, 2013 at 20:43 comment added user9072 Personally I hardly use the word "canonical". Yet, if one would not consider the field but only the multiplicative group (I think) one could show that there cannot be a functor (or likely I should say faithful functor or something) from cyclic groups to cyclic groups with distinguished generating element. (And in some sense it seems there is even no apparent way to "name" a distinguished generating element just knowing the group abstractly.)
Feb 19, 2013 at 20:26 comment added Matthieu Romagny I agree that the smallest integer $g$ such that $g.1$ is a generator in $(\mathbb{F}_p)^\times$ makes sense and is preserved by all field automorphisms. This supports the claim that there is a canonical generator. However this "canonical" generator clearly does not enjoy better algebraic or number-theoretic properties than the other generators, but in our daily experience canonical objects <em>do</em> have nice properties. I am starting to think that the statement that "there is no canonical generator" is just a way of speaking that carries hardly any solid mathematical content.
Feb 19, 2013 at 19:22 history edited user9072 CC BY-SA 3.0
expanded to reflect updated version of the question
Feb 19, 2013 at 14:49 history edited José Hdz. Stgo. CC BY-SA 3.0
added 1 characters in body
Feb 19, 2013 at 13:44 comment added user9072 The "known" in the in the discret logarithm proble is a bit sloppy, i should likely better say 'well-known to be believed to be hard'.
Feb 19, 2013 at 13:30 history answered user9072 CC BY-SA 3.0