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Oct 23, 2014 at 14:15 history edited Francesco Polizzi CC BY-SA 3.0
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Feb 19, 2013 at 8:53 history edited Francesco Polizzi CC BY-SA 3.0
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Feb 19, 2013 at 1:01 vote accept kiseki
Feb 18, 2013 at 14:46 comment added Laurent Moret-Bailly More generally: if $A$ is a local ring and $I$ an ideal such that $A$ is $I$-adically complete and separated, then $A$ is henselian if (and only if!) $A/I$ is henselian. This is easy by observing that each $A_n:=A/I^n$ is henselian (because $A_{n,\mathrm{red}}$ is) and then inductively lifting roots to $A$. See Raynaud, LNM 169, I, §2 where this result is given as an exercise.
Feb 18, 2013 at 14:24 history edited Francesco Polizzi CC BY-SA 3.0
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Feb 18, 2013 at 13:56 history answered Francesco Polizzi CC BY-SA 3.0