Timeline for totally ordered chain in the powerset with big cardinality
Current License: CC BY-SA 3.0
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Feb 21, 2013 at 16:20 | vote | accept | Toink | ||
Feb 17, 2013 at 1:53 | comment | added | Joel David Hamkins | Note that the $2^{\lt\kappa}=\kappa$ property, while sufficient, is not necessary. For example, it could be that $2^\beta=2^\kappa$ for some $\beta\lt\kappa$ with $2^{\lt\beta}\leq\kappa$, and in this case, we would still have the tree $2^{\lt\beta}$ of size at most $\kappa$, but still having $2^\kappa$ many cuts. | |
Feb 17, 2013 at 1:35 | history | edited | Joel David Hamkins | CC BY-SA 3.0 |
Added characterization
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Feb 17, 2013 at 1:08 | history | answered | Joel David Hamkins | CC BY-SA 3.0 |