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Feb 16, 2013 at 17:51 vote accept stepanp21
Feb 15, 2013 at 10:28 comment added Mark Wildon Thank you for the reference. As you say in your paper, it's a remarkable isomorphism.
Feb 14, 2013 at 14:32 comment added Abdelmalek Abdesselam ...the page 43 is the first of the article. The one where this isomorphism is mentioned is page 46.
Feb 14, 2013 at 14:17 comment added Abdelmalek Abdesselam @Mark: that symmetric plethysm is isomorphic to wedge^{k} sym^{d+k-1} via the so-called Wronskian isomorphism. See my paper with Chipalkatti in J. Pure App. Algebra vol. 210 p. 43. This is why the Cayley-Sylvester formula gives the answer for that case too.
Feb 14, 2013 at 4:45 comment added Mark Wildon When $n=2$ the plethysm ${\rm Sym^k}{\rm Sym^d}V$ is given by the Cayley-Sylvester formula. I can't see why this is equivalent to knowing your plethysm. But I think it should be possible to work out the constituents of $\bigwedge^k ({\rm Sym}^d V)$ using similar arguments with formal characters of ${\rm SL_2}(\mathbb{C})$.
Feb 14, 2013 at 4:39 answer added Mark Wildon timeline score: 8
Feb 13, 2013 at 22:39 history asked stepanp21 CC BY-SA 3.0