Skip to main content
8 events
when toggle format what by license comment
Feb 14, 2013 at 18:00 vote accept Jonathan Beardsley
Feb 13, 2013 at 8:13 history edited Ricardo Andrade
edited tags
Feb 13, 2013 at 5:35 answer added Peter May timeline score: 8
Feb 13, 2013 at 5:14 comment added Peter May This doesn't help answer your real question but gives your map f. F= GL_1S is the subspace of QS^0 = colim \Omega^n\Sigma^n consisting of stable maps of spheres of degree 1 or -1. Let SF(n) be the monoid under composition of maps S^n\to S^n of degree 1. Using one-point compactification of C^n$, U(n) embeds in SF(2n); passing to colimits gives U \to SF; passing to classifying spaces gives f: BU \to BSF. But the map is irrelevant to the classical construction of the Thom spectrum MU, which just uses the Thom spaces of the universal complex n-plane bundles directly.
Feb 12, 2013 at 20:51 comment added Jonathan Beardsley And yeah, thanks Mark. I'm trying to figure out how that's related.
Feb 12, 2013 at 20:49 comment added Jonathan Beardsley Sorry, ABGHR is the paper: arxiv.org/abs/0810.4535
Feb 12, 2013 at 19:57 comment added Mark Grant What is ABGHR? I guess you already know that a complex orientation on $E$ is the same as a map of ring spectra $MU\to E$.
Feb 12, 2013 at 19:21 history asked Jonathan Beardsley CC BY-SA 3.0