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Feb 12, 2013 at 5:12 comment added Theo Johnson-Freyd ... For abelian groups, I think I can do the infinitesimal case from a spectral-sequence argument, using the fact that the if the associated-graded of a filter abelian group is zero, then the filtered abelian group was already zero; but there, I don't even know "infinitesimal upper semicontinuity" except near exact complexes, and I really don't know how to say non-infinitesimal statements.
Feb 12, 2013 at 5:11 comment added Theo Johnson-Freyd @Mariano: Right, for finite-dimensional vector spaces I know how to do everything I've asked. Already for infinite-dimensional vector spaces, though, I know how to prove semicontinuity for "infinitesimal" open neighborhoods, but I don't know enough about infinite-dimensional vector spaces to say things finitely...
Feb 10, 2013 at 15:13 comment added Martin Brandenburg "I expect that there is a natural way to give the hom spaces in an abelian category, and thus the space of differentials, the structure of affine algebraic varieties;" I am not sure if this works without any assumption on the abelian category.
Feb 10, 2013 at 11:25 comment added Allen Knutson Mariano, I think you mean affine variety, with equations $d^2=0$.
Feb 10, 2013 at 9:13 comment added S. Carnahan Regarding your parting comment, I think it is reasonable to require that the zero element be closed in any topologized hom space.
Feb 10, 2013 at 6:07 comment added Mariano Suárez-Álvarez The set of complexes of vector spaces of given finite dimension vector "are" an affine space, and the dimension of their cohomology groups is a lower (upper? I never know which) semi-continuous function. Since it is possitive, that gives your continuity in that case.
Feb 10, 2013 at 5:54 history asked Theo Johnson-Freyd CC BY-SA 3.0