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Feb 9, 2013 at 0:16 comment added David Roberts Or rather, not circular, but the statement of the desired theorem is rather shallow :-)
Feb 9, 2013 at 0:15 comment added David Roberts Herein lies the problem: it gets a bit circular if I start defining a weak equivalence to be a map which induces an equivalence of stacks. In any case, I can get the result I want without depending on whether the approach I outline in the question works or not.
Feb 8, 2013 at 21:00 history answered David Carchedi CC BY-SA 3.0