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Feb 13, 2013 at 14:47 history edited Yuri Gurevich CC BY-SA 3.0
Final thanks
Feb 10, 2013 at 16:49 comment added GH from MO Your conjecture is false, see the Added part of my response.
Feb 10, 2013 at 16:20 comment added Noam D. Elkies [Greg Martin is right; my comment from yesterday (deleted, but appended here) is correct but answers a different question.]$$ $$ "It's known that $\sum_{n<x} r(n) = \pi x + O(x^\theta)$ for some $\theta$ slightly less than $1/3$. (Getting $1/3$ is standard; the conjecture is that it's true for any $\theta > 1/4$.) That's more than enough to get $\sum_{n=a}^{a+\Theta(\sqrt{a})} r(n) > 0$ for large $a$."
Feb 10, 2013 at 7:17 answer added Greg Martin timeline score: 8
Feb 10, 2013 at 4:39 history edited Yuri Gurevich CC BY-SA 3.0
Narrowed the question to a specific conjecture.
Feb 9, 2013 at 18:14 history edited Yuri Gurevich
edited tags
Feb 9, 2013 at 18:06 history edited Yuri Gurevich CC BY-SA 3.0
Narrowing the question
Feb 8, 2013 at 20:57 answer added GH from MO timeline score: 11
Feb 8, 2013 at 19:23 comment added Abhinav Kumar The average value is $\pi$, as you can convince yourself by counting the integer points inside a large circle. For more information, see mathworld.wolfram.com/SumofSquaresFunction.html or (say) a book on analytic number theory ...
Feb 8, 2013 at 19:06 history asked Yuri Gurevich CC BY-SA 3.0