Timeline for Does this subgroup of "even braids" have a name?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 9, 2013 at 10:10 | comment | added | Mark Grant | Thanks Andy (and Vladimir) for this very interesting and informative answer. | |
| Feb 9, 2013 at 10:09 | vote | accept | Mark Grant | ||
| Feb 8, 2013 at 21:34 | history | edited | Andy Putman | CC BY-SA 3.0 |
added 397 characters in body
|
| Feb 8, 2013 at 21:29 | comment | added | Andy Putman | @Vladimir Dotsenko : Thanks for letting me know about that paper; I had not seen it before! It shows that the "large $n$" condition I included is not necessary. | |
| Feb 7, 2013 at 16:23 | comment | added | Vladimir Dotsenko | That's very nice. A quick remark on what you say ("it's quite hard to decompose $H^k(PB_n;\mathbb{Q})$ into irreducibles"): a description of $H^*(PB_n;\mathbb{Q})$ as a representation is done by Felder and Veselov (e.g. arxiv.org/abs/math/0311190), they prove that it is isomorphic to $2 Ind^{S_n}_{\langle (12)\rangle}(1)$. This clearly shows that the alternating representation does not occur at all (Frobenius reciprocity). | |
| Feb 7, 2013 at 14:22 | history | answered | Andy Putman | CC BY-SA 3.0 |