Timeline for Explicit 3-cocycle of a cyclic group
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 8, 2014 at 0:10 | answer | added | wonderich | timeline score: 8 | |
| Feb 8, 2013 at 2:09 | comment | added | user31234 | These answers are both very useful! | |
| Feb 7, 2013 at 23:01 | comment | added | Ralph | An explicit formula is given in Proposition 2.3 in this paper: arxiv.org/pdf/1206.5402.pdf | |
| Feb 7, 2013 at 13:37 | comment | added | Martin Bright | If $G$ is cyclic, then $H^1(G,M)$ is isomorphic to $H^3(G,M)$ for any $M$, and an isomorphism is given by cup-product with a generator of $H^2(G,\mathbb{Z})$. So one approach to your question would be to write down a generator for $H^1(\mathbb{Z}/n\mathbb{Z},U(1))$ and a generator for $H^2(\mathbb{Z}/n\mathbb{Z},\mathbb{Z})$, which are both easy, and then try to compute an explicit cocycle representing their cup product. This may or may not satisfy your "uniformity" condition, depending on exactly what you mean. | |
| Feb 7, 2013 at 12:56 | history | asked | user31234 | CC BY-SA 3.0 |