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Feb 7, 2013 at 10:21 comment added Liviu Nicolaescu Have a look at Brieskorn's book Plane Algebraic Curves. He has a lot historical data in that book and you might find the answer there.
Feb 7, 2013 at 4:35 comment added Vivek Shende it may be helpful to know that the 'reason' this number is a homeomorphism invariant is that it's equal to the linking number of the links of $X$ and $Y$ (i.e. you intersect them with the boundary of a small ball around $(0,0)$).
Feb 6, 2013 at 18:48 history asked germ_dude CC BY-SA 3.0