Timeline for Geodesics in polyhedral graphs
Current License: CC BY-SA 3.0
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
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| Feb 6, 2013 at 17:56 | comment | added | Hans-Peter Stricker | @Joseph: To your first question: no, two geodesic edges are supposed to be the building blocks of longer geodesics. I only wanted to make the 2-edge-case clear in advance. To your second: Two consecutive edges are not a pre-geodesic because they are not a unique shortest path. | |
| Feb 6, 2013 at 1:15 | comment | added | Joseph O'Rourke | Am I interpreting this correctly? Every pre-geodesic, and therefore every geodesic, is exactly two edges long...? In your square example, label three consecutive vertices $u,v,u'$. So $(u,v,u')$ is a pre-geodesic. You claim it is not a geodesic. But surely there is no other edge $f$ incident to $v$, so it seems $(u,v,u')$ is a geodesic according to your definition. | |
| Feb 5, 2013 at 22:43 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Feb 5, 2013 at 22:17 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Feb 5, 2013 at 21:56 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Feb 5, 2013 at 20:04 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Feb 5, 2013 at 0:46 | history | asked | Hans-Peter Stricker | CC BY-SA 3.0 |